Elastic Potential Energy

Up Spring Scales Elastic Potential Energy Bouncing

Work and elastic potential energy

In order to compress or stretch a spring, you have to do work.  You must exert a force on the spring equal in magnitude to the force the spring exerts on you, but opposite in direction.  The force you exert is in the direction of the displacement.  You therefore do work.

The average force you exert as you change the displacement from 0 to x is (1/2)kx.  The work you do when stretching or compressing a spring therefore is

W = force*distance = (1/2)kx*x = (1/2)kx2.

As you do work, you transfer energy to the spring. The elastic potential energy stored in the spring is U = (1/2)kx2.

Problem:

When a 4 kg mass is hung vertically on a certain light spring that obeys Hooke's law, the spring stretches 2.5 cm.  If the 4 kg mass is removed,
(a) how far will the spring stretch if a 1.5 kg mass is hung on it, and
(b) how much work must an external agent do to stretch the same spring 4 cm from its unstretched position?

Problem:

If it takes 4J of work to stretch a Hooke's law spring 10 cm from its unstretched length, determine the extra work required to stretch it an additional 10 cm.