Postulate: Every elementary particle is either a fermion or a boson. A state of many identical particles is totally antisymmetric with respect to the interchange of any two particles if they are fermions, and it is totally symmetric if they are bosons. No two identical fermions can have exactly the same set of quantum numbers. This is called the Pauli exclusion principle.
LS coupling
We assume that the non-central part of the electrostatic interaction is much
bigger than the spin-orbit interaction. (This is usually true for light
multi-electron atoms.) The electrostatic interaction leads to a splitting of
the level corresponding to a given electron configuration into a number of
sublevels characterized by different values of the total orbital angular
momentum of the electrons, L, and their total
spin, S. The operator for the electrostatic
interaction commutes with L = l1+l2+l2+... and
S
= s1+s2+s3+... . Some of the values of
L
and S obtained from the general rules for addition of angular momenta can
correspond to states forbidden by the Pauli principle. Filled shells do
not contribute to the total orbital angular momentum L and the total spin S. To each
allowed term LS belong
(2L+1)(2S+1) states, differing by the values of ML and MS.
The spin-orbit interaction leads to a splitting of the term LS into a number of
components corresponding to different values of the total angular momentum J.
But it does not completely remove the degeneracy. Each J component is
degenerate with a multiplicity of 2J+1.
∑J(2J+1) = (2L+1)(2S+1).
In the LS coupling scheme, a term is designated by 2S+1LJ.
2S+1 is called the multiplicity of the term.
Which terms corresponding to a given configuration have the lowest
energy?
Hund's Rule (established empirically to find the ground state term)