A wire carries a steady current of 2.4 A. A straight section of the wire is
0.75 m long and lies along the x-axis within a uniform field
**B **= (1.6**k**) T.
If the current is in the positive x-direction, what is the magnetic force on the
section of wire.

Solution:

- Concepts:

The Lorentz force on a wire, F = ∫_{V }I d**l**x**B**(**r**) - Reasoning:

We are asked to find the magnetic force on a section of wire. - Details of the calculation:

The force on the wire is given by**F**= I**L**x**B**.The direction of

**L**x**B**is the -**j**direction. Since**L**and**B**are perpendicular to each other

F = ILB = (2.4 A)(0.75 m)(1.6 T) = 2.88 N.

The force on the section of wire is**F**= -2.88 N**j**.