The wave equation

In lih materials in regions with  rf = 0   and  jf = 0  both E  and B  satisfy the wave equation.

(SI units) (Gaussian units)

Sinusoidal plane wave solutions    exist.  We have

,

   (SI units),              (Gaussian units).

In regions with  rf=0  and   jf=scE  both E and B satisfy the damped wave equation.

(SI units) (Gaussian units)
Now
i.e. k is complex, the wave damps out

The skin depth is defined as the distance it takes to reduce the amplitude by a factor of .

Plane waves at boundaries

(SI units) (Gaussian units)

are the boundary conditions the electromagnetic fields have to satisfy on any boundary.   For waves propagating across a dielectric-dielectric boundary or from a dielectric into a conductor we use From these boundary conditions we derive the law or reflection, qi = qr, and the law of refraction, (Snell’s law), n1sinqi = n2sinqt,  for a wave propagating from a medium with index of refraction n1 into a medium with index of refraction n2.  Here qi, qr, and qt are the angles the incident, reflected, and transmitted wave vectors make with the normal to the boundary.

The plane of incidence is the plane containing the wave vector ki and the normal to the boundary.  A linear polarized wave has p-polarization if E lies in the plane of incidence, and it has s-polarization if E is perpendicular to the plane of incidence.  The reflection coefficients for s and p polarization are , and the transmission coefficients for s and p polarization are .

Here       and        .

The reflectance is    and the transmittance is   

We have R+T=1  (energy conservation).

For conductors  are complex numbers.

Polarization by reflection

When qi = qB, the Brewster angle, then only light with s-polarization is reflected.  We have

Total internal reflection

If n2<n1 , then for  we have total internal reflection.  The wave vector kt then has a component parallel to the interface which is real and a component perpendicular to the interface which is imaginary.

Reflection by a good conductor

For good conductors The wave does not penetrate into the conductor.  We then use the boundary conditions