The Hamilton-Jacobi equation

Assume we have a system with a Hamiltonian .  If we make a canonical transformation with a generating function F2(q,P,t) such that

    and    

we obtain the Hamilton-Jacobi equation.  The function F2 is called Hamilton’s principal function S, and the Hamilton-Jacobi equation is

.

Since K=0,

,

i.e. all new variables are constant in time.  Therefore  , where the a’s are the transformed momenta.  We have

.

To solve a problem using the Hamilton-Jacobi method
solve the Hamilton-Jacobi equation     .
The a’s are the transformed momenta.  Find the transformed coordinates from    
These equations give the coordinates q as a function of 2n constants a and b.  Solve for q.  Solve for p by differentiating    

Simplification:

If H=H(q,p), then

   

Here a1 is a constant, often it is the energy.  W(q,a) is called Hamilton’s characteristic functionW(q,a) is a generating function for its own canonical transformation.

To solve a problem using the Hamilton’s characteristic function
solve     .
The a’s are the transformed momenta.  Find the transformed coordinates from    
These equations give the coordinates q as a function of 2n constants a and b.  Solve for q.  Solve for p by differentiating    

Action-angle variables

Assume a conservative system with one degree of freedom which has periodic motion.  Let H(q,p)=a, p=p(q,a).  Define         The integration is over one complete period of the motion.  J is called the action variable, and it is taken to be the new constant momentum in Hamilton’s principal function      Now we look at the canonical transformation generated by W(q,J).  J is the new constant momentum and w the new coordinate.  We have

  w is called the angle variablen is the frequency associated with the periodic motion.  We can find n without finding a complete solution of the problem.