Let H=H0+W. Let
be an
orthonormal eigenbasis of H0,
.
Here i denotes the degeneracy. Let H|yp>=Ep|yp>.
Expand Ep and |yp>.
Ep=E0p+E1p+E2p+...
, |yp>=|yp0>+|yp1>+|yp2>+...
. Stationary perturbation theory yields Ep=E0p,
If |fp>
is not degenerate then |yp0>=|fp>.
E1p and api are found
from
. We have to
diagonalize the matrix of W in the subspace spanned by the degenerate states
If E0p is not degenerate
then
.
This is the first order energy correction for non-degenerate states.
If E0p is not degenerate then
.
This is the first order correction to a non-degenerate eigenvector.
The second order energy correction for non- degenerate states is
.
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Let H=H0+W(t). Let
be an
orthonormal eigenbasis of H0,
.
Let
. Assume that at t=0 the system is
in the state |fi>. The probability of
finding the system in the state |ff> (f¹i)
at time t is
in first order time-dependent perturbation theory.
Assume there exists a group of states nearly equal in energy
Let
be the density of final
states, i.e.
is the number of final states in the
interval dE characterized by some discrete index b.
Let W(t)=Wexp(±iwt).
Then
the transition probability per unit time is
given by
. This is Fermis golden rule.
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Consider an arbitrary physical system with a time-independent Hamiltonian.
Let {En}
be its eigenvalues and {|fn} its
eigenstates. H|fn>=En|fn>.
Let E0 denote the energy of the ground state. If |y>
is an arbitrary ket in the state space of the system, then
This is the basis for the variational method.
Choose a family of kets |y(a)>
which satisfy the boundary conditions and which depend on a number of free
parameters a. Calculate the mean value <H>(a).
Minimize <H>(a) with
respect to a. The minimal value thus obtained constitutes an
approximation to the ground state energy E0 of the system.
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Postulate: Every elementary particle is either a fermion or a boson. A state of many identical particles is totally antisymmetric with respect to the interchange of any two particles if they are fermions, and it is totally symmetric if they are bosons. No two identical fermions can have exactly the same set of quantum numbers. This is called the Pauli exclusion principle.
LS coupling
We assume that the non-central part of the electrostatic interaction is much bigger than the spin-orbit interaction. (This is usually true for light multi-electron atoms.) The electrostatic interaction leads to a splitting of the level corresponding to a given electron configuration into a number of sublevels characterized by different values of the total orbital angular momentum of the electrons, L, and their total spin, S. The operator for the electrostatic interaction commutes with L = l1+l2+l2+… and S = s1+s2+s3+… . To each term LS belong (2L+1)(2S+1) states, differing by the values of ML and MS. The spin-orbit interaction leads to a splitting of the term LS into a number of components corresponding to different values of the total angular momentum J. But it does not completely remove the degeneracy. Each J component is degenerate with a multiplicity of 2J+1.
SJ(2J+1) = (2L+1)(2S+1).
In the LS coupling scheme, a term is designated by 2S+1LJ. 2S+1 is called the multiplicity of the term.
Which terms corresponding to a given configuration have the lowest energy?
Hund's Rule (established empirically)
| The level with the largest multiplicity has the lowest energy. | |||
| For a given multiplicity, the level with the largest value of L has the lowest energy. | |||
For less than half-filled shells:
| |||
For more than half-filled shells:
| |||
| When the number of electrons is 2l + 1, i.e. when the shell is half filled, there is no multiplet splitting. |