Let |yS(t0)> be a state
vector in the Schroedinger picture, i.e. let it
evolve in time and let its evolution be described by the Schroedinger equation.
Then
The Schroedinger picture implies an
active unitary
transformation. The state vector is transformed, but all operators are constant in
time unless they contain time explicitly. The basis vectors are not changing.
The
operators are defined through their action on the basis vectors.
The Heisenberg picture implies the
equivalent passive unitary transformation. The state vector is constant, |yH>=|yS(t0)>=U(t0,t)|yS(t)>, |yH>=UT(t,t0)|yS(t)>.
However the basis vectors are changing, and
therefore the operators are changing. The operator AH(t) which does to
the new basis vectors what AS(t) does to the old basis vectors is given
by
.
describes the evolution of the operators in the Heisenberg picture.
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Assume the Hamiltonian of an arbitrary system is H0(t), and the corresponding evolution operator is U0(t,t0). Assume that the Hamiltonian of a given system is H(t)=H0(t)+W(t). The state vector for this system in the interaction picture is |yI(t)>=U0T(t,t0)|yS(t)>.
describes the evolution of |yI(t)>.
In integral form we have ![]()
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¯_________________________
This integral equation can be solved by iteration.
.
The interaction picture assigns part of the time dependence to the state vectors, and part to the operators. The equation for the evolution of operators in the interaction picture is
.
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In the Schroedinger picture the evolution of the mean value
of an observable is given by ![]()
Ehrenfests theorem
:![]()
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Let
We introduce the
pure state density operator
, i.e.
the projector onto the state
, and the density matrix with matrix elements
.
In terms of the density operator
we express:
We are dealing with a statistical mixture of states,
if we have incomplete information and only know that a system may be in a state |yk> with probability pk, with
.
For such a system we introduce the density operator
and the density matrix with matrix elements
.
In terms of the density operator we express: