Postulates of Quantum Mechanics

bulletProblem:

A particle is described by the wavefunction y(x)=(2L)-1/2 for |x| £ L, and y(x)=0 for |x| > L.

(a)  What is the probability P(p) of finding the particle with momentum p?

(b)  Sketch the probability P(p) and discuss it in relation to the uncertainty principle.

(c)  Let P1 be the probability of finding the particle with momentum h/4L.  Show that P1/P(0)=4/p2.

bulletSolution:

wpe2.jpg (30140 bytes)

bulletProblem:

(a)  The wavefunction for a spinless particle moving in a central potential V(r)=V(r) is y=A sinq f(r), where A is a constant, and What is the probability that a measurement of the angular momentum quantum number l would yield 0? 1?

(b)  In the same potential suppose that y=Bsinq sinf f(r), where B is a constant, and What values and with what probabilities would be obtained for measurements of the total angular momentum and the z-component of the angular momentum?

bulletSolution:

wpe1.jpg (35496 bytes)

wpe2.jpg (12310 bytes)

bulletProblem:

A particle of mass m is contained in a one-dimensional impenetrable box extending from x=-L/2 to x=L/2. The particle is in its ground state. The walls of the box are now moved out, symmetrically an instantaneously, to form a box extending from x=-L to x=L.

(a)  Calculate the probability, that after this sudden expansion the particle will be in the ground state.
(b)  What is the probability that it will be found in the first excited state?
(c)  What is the expectation value of the energy after the rapid expansion? Answer without calculation.

bulletSolution:

wpe1.jpg (34839 bytes)

bulletProblem:

Two infinite potential wells are extending from x=-a to x= 0 and from x= 0 to x=a, respectively.  A particle is in its ground state in the left well.  At t=0 the barrier at x=0 is removed.  What is the probability of finding the particle in the first excited state of the new well?

bulletSolution:

wpe3.jpg (19576 bytes)

bulletProblem:
An atom with L=0 and S=½ is initially in its ground state with Sz=-½.  A field H1i is turned on at t=0 so that the effective Hamiltonian may be taken to be H=H0-(e/mec)SxH1q(t), where H0 is the atomic Hamiltonian with H1=0.  Thus both Sz and Sz=-½ states have the same eigenvalue of H0 in the ground state.
(a)  What is the probability P, to lowest order in H1, that the atom remains in the state  |S=½,Sz=-½> at time t?  Here , e is the magnitude of the electron charge, me is the electron mass, and c is the velocity of light in the vacuum.
(b)  Under what conditions on t will P=0?
bulletSolution:
Concepts, principles, relations that apply to the problem:
Two level systems, the postulates of quantum mechanics.

Why do they apply?
Assume that the energy of the twofold degenerate ground state is much lower than the energy of any excited state, and approximate the system by a two-level system.  Then the eigenstates of H0 are known and form a basis for the two-dimensional state space of the system.  We can diagonalize the matrix of H and find the eigenvalues of H and the eigenfunctions of H as linear combinations of eigenfunctions of H0.  The initial state is a linear combination of these eigenstates, and we therefore know how it evolves in time.  The postulates of quantum mechanics tell us that P=|<y (0)|y (t)>|2.

How do they apply?
Denote the two levels by |+> and |->H0|+>=E0|+>, H0|->=E0|->, the system is degenerate. {|+>,|->} are the eigenstates of Sz.   .

At t=0 the system is in the state |->, but the Hamiltonian is H0+W=H,   with   .   In the {|+>,|->} the matrix of W is  .  The matrix of H is  .

The eigenvalues of H are  , and the corresponding eigenfunctions are  .

Details of the calculations:

In this problem . .

. .  

If  then P-(t)=0.

If   with n an odd integer, then P-(t)=0.