
The eigenvalue equation
E>0,
can be put into the form
with
E=h2k2/(2m)
The solutions to this equation may be written in the form
![]()
where f0(r) is a solution of the
homogeneous equation
and G(r)
is a solution of ![]()
Verify:
![]()
0 acts only on r
![]()
d(r-r')
The solutions of
are
These are two
linearly independent solutions of a second order differential equation.
(To verify that these are the solutions use ![]()
)
For a stationary scattering state we might choose f0(r)=eikz and G(r)=G+(r).
![]()
If |r'|<<|r| then
and ![]()
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This yields an integral expression for the scattering amplitude fk(q,f).
![]()
).
This procedure can be repeated and yields the Born expansion. The Born approximation is the first term in the Born expansion.
The scattering amplitude in the Born approximation is given by
![]()
Here ![]()
The scattering amplitude is proportional to the Fourier transform of the potential energy.
is the differential
scattering cross section in the Born approximation.
![]()
Let
As a®0
the potential becomes the Coulomb potential. Then the scattering amplitude in the Born
approximation is given by
![]()
Choose the coordinate system such that
Then
![]()

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![]()
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Often you want to know the scattering cross section as a function of the scattering
angle and not as a function of the momentum transfer. Let q'
be the angle between ki and kf. Then ![]()

Then 
![]()
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Let a®0, V0=Z1Z2e2. Then
![]()
This is Rutherfords formula. The Born approximation for the Yukawa potential gives Rutherfords formula as a®0. The total cross section skB®¥.
The total cross section is infinite, because the Coulomb potential has infinite range.When is the Born approximation a good approximation?
In the integral
we are replacing the exact solution fk(r')
by the asymptotic incident wave eikz'. Therefore fk(r')
and eikz' should not be too different inside the range of the potential,
i.e. in the region where U(r) contributes appreciably to the integral.
We therefore need that
.
In the
high k limit this inequality is easily satisfied because the integrand oscillates
rapidly. We can also satisfy the condition if the scattering potential is weak.
| Solution: For fast electrons we can use the Born approximation. We then have
with q=k'-k, k the incident wave
vector and
[
where
If we assume that F(q)=1, i.e. that the incoming electron sees a screened nucleus of charge 1, we obtain the Rutherford scattering cross section. |