
Let us first take a closer look at those free spherical waves. The Hamiltonian of a
free particle is
Since [Pi,Pj]=0,
(i,j=x,y,z), we have [H0,P]=0 and we can find
common eigenfunctions of H0, Px, Py, and Pz.
The observables Px, Py, and Pz form a
C.S.C.O. for a spinless particle. The common eigenstates form a basis {|p>}.
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The wave functions associated with the kets |p> are the plane waves
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Introducing the wave vector
we
define the ket
Since |k>
is proportional to |p> we have
The eigenstates of H0 are infinitely degenerate. The normalization and closure relation for {|k>} are written <k|k'>=d(k-k'), òd3k|k><k|=I. The Hamiltonian of a free particle also commutes with L2 and Lz. (We can view a free particle as a particle in a central potential of zero strength.) The observables H0, L2 and Lz form a C.S.C.O. for a spinless particle. The common eigenstates form a basis {|k,l,m>}.
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The wave functions associated with the kets |k,l,m> are the free spherical waves.
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For a free particle the radial functions fkl(r) are solutions to the differential equation
With r=kr, and
this equation becomes
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This is the spherical Bessel equation. Its solutions are the spherical Bessel functions jl(r) and nl(r) and linear combinations of both.
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As
Therefore only jl(r) is an acceptable wavefunction for a free particle.
Using the
orthonormality of the spherical Bessel functions we have
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The free spherical waves are orthogonal and complete. Let us take a closer look at jl(r).
As r®0, the lowest power in r dominates.
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Double factorial notation:
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As r®¥ the highest power in r dominates.
As we keep on differentiating, the highest power will always come from the derivative of the first term. We therefore have
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The probability of finding a particle in a free spherical wave eigenstate of the
Hamiltonian H0 near the origin, within a solid angle dW0 and between r and r+dr is proportional to
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The probability of finding the particle near the origin decreases as l
increases. If
then the
probability of finding the particle between zero and r is negligible.
Note: To show this, you cannot just require that
in the region
because the wavefunction is a continuum
wavefunction and cannot be normalized to one. You have to build a wave packet and show
that the wave packet does not penetrate the region
Because the wave packet does not penetrate, a particle in an eigenstate |klm>
of H0 is practically unaffected by what happens inside a sphere centered
at the origin of radius ![]()
Let us use classical physics as a guide. In classical mechanics, a free particle with
angular momentum L about the origin and momentum p moves in a
straight line with closest distance to the origin b=L/p. b is called the
impact parameter relative to the origin. If ![]()
bl(k) can thus be interpreted semi classically. In quantum mechanics, bl(k)
is the radius where
is equal to the
total energy of the free particle.
For r<bl(k), in the classically forbidden region, the eigenfunctions |klm> can only have an approximately exponentially decaying tail.