A particle of mass m is in a cubical well if side L, corresponding to the
potential energy function
U(r) = 0 if |x|, |y| and |z| < L/2, U(r) = ∞ otherwise.
(a) What is its ground-state energy?
(b) What is the energy of the first excited state? Is this energy level degenerate or non-degenerate? Explain!
(c) Suppose 20 identical, non-interacting particles of mass m and spin ½ are in this well. What is the ground state energy of this system? Is this ground state degenerate or non-degenerate? Explain!
Consider a "box" that is a two dimensional square well with sides of length L
x L. Inside the well the potential is U = 0, outside the well the
potential is infinite.
(a) Let the box contain one particle of mass M. Determine (or write down) the general set of wave functions Φ(x,y), find the allowed energies for these states and identify the eigenvalues kx and ky for the particle.
(b) Write down the three lowest energy eigenvalues and note the degeneracies, if any.
(c) Make a plot, as a function of the eigenvalues kx and ky, showing the allowed states. On this plot, consider a circle of radius k = (kx2 + ky2)½, with k large. What is the area of this circle? Approximately how many states are contained in this circle?
(d) Now suppose that the same box contains N identical, non-interacting Fermi particles, each with mass M and spin ½. We have N >> 1. Find the energy of the highest occupied state, if the system is in its ground state.
(e) For the N particle system in part d, calculate its total energy
Details of the calculation:
(a) The eigenfunctions and eigenvalues of the 2D infinite square well are
Φnm(x,y) = (2/L)sin(kxx)sin(kyy), with kx = πn/L, ky = πm/L, n, m = 1, 2, ... .
The associated eigenvalues are
Enm = (n2 + m2)π2ħ2/(2ML2) = (kx2 + ky2)ħ2/(2M).
(b) The three lowest energy
E11 = π2ħ2/(ML2), E12 = E21 = 5π2ħ2/(2ML2),
E22 = 4π2ħ2/(ML2), E13 = E31 = 5π2ħ2/(ML2).
The eigenvalue 5π2ħ2/(2ML2) is degenerate.
(c) kx = πn/L, ky = πm/L, ∆kx = ∆ky = π/L.
The area of a circle in 2D k-space is A = πk2.
The number of states in the circle is Nstates = (A/4)/(π/L)2 = k2L2/(4π).
Only positive values of kx and ky are allowed.
The density of states in k-space is n(k) = dN/dk = kL2/(2π).
(d) Each state can be occupied by two particles, one with spin up and one with spin down.
If the system is in its ground state all the lowest energy levels are filled.
The energy of the highest occupied state is Emax = ħ2kmax2/(2M),
where Nparticles = (kmax2L2/(2π) or kmax2 = 2πNparticles/L2.
(e) The number of states between k and k + dk that can be occupied is 2n(k)dk = (kL2/π)dk.
The total energy of the system is
Et = ∫0kmax(ħ2k'2/(2M))2n(k')dk' = ∫0kmax(ħ2k'2/(2M))(k'L2/π))dk'
= (ħ2L2/(2Mπ)) ∫0kmax k'3dk' = (ħ2kmax4L2/(8Mπ)) .
Et = ħ2πN2particles/(2ML2)).
Consider an ideal 3D Fermi gas comprising N non-interacting fermions, each
of mass M, in a container of volume V at T = 0
(a) Find the Fermi energy.
(b) Find ρ(E)dE the number of quantum states whose energy lies in the range
E to E + dE.
(c) Find the average energy per fermion at absolute zero by making a direct calculation of U(0)/N, where U(0) is energy at T = 0 for N fermions. Express this in terms of the Fermi energy, EF.